TRIGONOMETRY :
Trigonometry developed from a need to compute angles and distances in such fields as astronomy, mapmaking, surveying, and artillery range finding. Problems involving angles and distances in one plane are covered in plane trigonometry. Applications to similar problems in more than one plane of three-dimensional space are considered in spherical trigonometry.
CHAPTER NAME | TRIGONOMETRY |
SUBJECT | MATHEMATICS |
CLASS | 11th |
NOTES LANGUAGE | ENGLISH |
NO. OF PAGES | 14 |
SYALLBUS FOR TRIGONOMETRY :
- Angles and their measures in degrees and in radians.
- Trigonometric ratios.
- Trigonometric identities Sum and difference formulae.
- Multiple and Sub-multiple angles.
- Inverse trigonometric functions.
- Applications-Height and distance, properties of triangles.
YOUTUBE VIDEOS FOR REVISION : -
Q. No.1: In any triangle ABC, prove that a sin (B – C) + b sin (C – A) + c sin (A – B) = 0.
Solution:
In any triangle ABC,
a/sin A = b/sin B = c/sin C = k
a = k sin A, b = k sin B, c = k sin C
LHS
= a sin (B – C) + b sin (C – A) + c sin (A – B)
= k sin A [sin B cos C – cos B sin C] + k sin B [sin C cos A – cos C sin A] + k sin C [sin A cos B – cos A sin B]
= k sin A sin B cos C – k sin A cos B sin C + k sin B sin C cos A – k sin B cos C sin A + k sin C sin A cos B – k sin C cos A sin B
= 0
= RHS
Hence proved that a sin (B – C) + b sin (C – A) + c sin (A – B) = 0.
Q.No.2: Find the radius of the circle in which a central angle of 60° intercepts an arc of length 37.4 cm (use π = 22/7).
Solution:
Given,
Length of the arc = l = 37.4 cm
Central angle = θ = 60° = 60π/180 radian = π/3 radians
We know that,
r = l/θ
= (37.4) * (π / 3)
= (37.4) / [22 / 7 * 3]
= 35.7 cm
Hence, the radius of the circle is 35.7 cm.
Q. No.3: A wheel makes 360 revolutions in one minute. Through how many radians does it turn in one second?
Solution:
Given,
Number of revolutions made by the wheel in 1 minute = 360
1 minute = 60 seconds
Number of revolutions in 1 second = 360/60 = 6
Angle made in 1 revolution = 360°
Angles made in 6 revolutions = 6 × 360°
Radian measure of the angle in 6 revolutions = 6 × 360 × π/180
= 6 × 2 × π
= 12π
Hence, the wheel turns 12π radians in one second.
Q. No. 4: Find the value of cos 570° sin 510° + sin (-330°) cos (-390°).
Solution:
LHS =cos (570)sin (510) + sin (- 330)cos (- 390)
= cos (570) sin (510) + [ – sin (330) ]cos (390) [ because sin( – x ) = – sin x and cos( – x ) = cos x ]
= cos (570)sin(510) – sin (330)
= cos (90 * 6 + 30) sin (90 * 5 + 60) – sin (90 * 3 + 60) cos (90 * 4 + 30)
= – cos (30) cos (60) – [ – cos (60) ] cos (30)
= – cos (30) cos (60) + cos (30) sin (60)
= 0
Q. No. 5: The value of cos 1° cos 2° cos 3° … cos 179° is
(a) 1/√2
(b) 0
(c) 1
(d) -1
Sol: (b)
Since cos 90° = 0, we have
cos 1° cos 2° cos 3° …cos 90°… cos 179° = 0
6.Derive the values of the angle
a. sin18∘sin18∘
b. tan15∘tan15∘
c. sin6712∘sin6712∘
7.Prove that
cos55∘+cos65∘+cos175∘=0cos55∘+cos65∘+cos175∘=0
8. If y=cos2x+sin4xy=cos2x+sin4x for all values of x, then prove that
34≤y≤134≤y≤1
9.Find the solution of the trigonometric equation 2tan2x+sec2x=22tan2x+sec2x=2 in the range [0,2π][0,2π]
11.Which of the following is not correct?
(A) sin A = –1/5
(B) cos A = 1
(C) sec A =1/2
(D) tan A = 20
10.Show that 2sin2y+4cos(x+y)sinxsiny+cos2(x+y)=cos2x
#RELATION
#LOGARITHM
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